Let’s use the same payouts as we did in Lesson 1
- Somebeachsomewhere 7.20 4.10 2.30
- Cam Fella 3.90 2.20
- A Worthy Lad 2.80
$2.00 Exactor payout 1-2 pays 28.00 $2.00 Triactor payout 1-2-3 98.00
Exactor betting is picking the 1st and 2nd place horse in the exact order.
The minimum amount to wager is 1 dollar.
So above if you bet a 1 dollar exactor 1-2, and Somebeachsomewhere was 1 and Cam Fella was 2 and finished like it did above you would win the exactor payout. Since you bet a 1 dollar exactor you would get 14.00 or half the
$2 dollar payout.
You can play a box Exactor which means your numbers can finish in any order, and you still win. So if you did a 1 dollar box exactor 1-2 in the above scenario you would win ½ the payout since the Exactor payout is based on a 2 dollar wager, or 14 dollars for your 2 dollars investment.
You can play more than 2 horses in a Boxed exactor.
If you boxed 1-2-3 in the above case it would cost you 6 dollars (1 dollar for each combination times 6 different combinations)
If you were to box 4 horses, it would cost 12 dollars. (1 dollar times 12 combinations)
The easiest way to figure out the cost is multiply (the total number of horses) by 1 less.
So 3 horse box costs 3 x 2 or 6 combinations x your bet amount. If you bet a 1 dollar box its $6.00
4 horse box costs 4 x 3 or 12 combinations x your bet amount. If you bet a 1 dollar box its $12.00
This also works with triactors.
3 horse box 3 x 2 x 1 or 6 combinations times the dollar amount wagered
4 horse box 4 x 3 x 2 or 24 combinations times the dollar amount wagered
So a 1 dollar triactor box 1-2-3 would cost 6 dollars, and a 1 dollar triactor box 1-2-3-4 would cost 24 dollars.
If you want to play the exactor or triactor but don’t want to spend 12 or 24 dollars, you can WHEEL a horse and reduce your expense.
Lets say you really like Somebeachsomewhere, but aren’t sure he will win, you could do a wheel exactor 1 with any number of horses in 2nd place, and if you think he might be 2nd, you could reverse it, with any number of horses with 1. (example. 1 with 2345 and 2345 with 1)
Lets say I like 1-2-3, and I think Somebeachsomewhere number 1 is going to be 1st or 2nd.
I could do a 1 dollar wheel exactor 1 with 2-3, and 2-3 with 1. The total cost is only 4 dollars, and Somebeachsomewhere has to finish 1st or 2nd, with Cam Fella or A Worthy Lad 1st or 2nd in order for me to win. Since it’s a 1 dollar wager, I would get half the payout, which is based on a 2 dollar wager.
You can do the same exact thing with triactors. Again to find out how much it was cost, simply multiply the 1st group of horses, by the 2nd group minus 1 horse…(unless no horses are the same) (ie. 1 with 2 with 3-4-5-6-7 would cost 1 x 1 x 5, multiplied by the dollar amount per wager)
So If I had a 7 horse race and I bet 1 dollar triactor (1 with All with All) it would cost me
One x 6 horses x 5 horses or 30 dollars total. If Somebeachsomewhere won, and I had all for 2nd and 3rd, I would win half the triactor payout. You can wheel as many horses as you want in each position.
For example, 1 dollar triactor wheel 1 with 2-3-4 with 2-3-4-5-6-7.
In this scenario, 1 must win, 2, 3 or 4 must be 2nd, and 2,3,4,5, 6 or 7 must be third.
The cost would be 1 x 3 x 5, (since the 2, 3 and 4 horses are in both places) you can’t have a 1-2-2 triactor, or a 1-4-4 triactor…..
The actual potential winning combinations on your ticket would be
1-2-3, 1-2-4, 1-2-5, 1-2-6, 1-2-7, 1-3-2, 1-3-4, 1-3-5, 1-3-6, 1-3-7, 1-4-2, 1-4-3, 1-4-5, 1-4-6, and 1-4-7. 15 combinations x 1 dollar per combination equals $15 dollars.
If you have any questions, you can go to the information area of the Mutuels, or ask Gord Dougan or Andrew Hughes who will be happy to help.