**Lesson 2 **

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Let’s use the same payouts as we did in Lesson 1

Race 1

- Somebeachsomewhere 7.20 4.10 2.30
- Cam Fella 3.90 2.20
- A Worthy Lad 2.80

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$2.00 Exactor payout 1-2 pays 28.00 $2.00 Triactor payout 1-2-3 98.00

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**Exactor**

Exactor betting is picking the 1^{st} and 2^{nd} place horse in the exact order.

The minimum amount to wager is 1 dollar.

So above if you bet a 1 dollar exactor 1-2, and Somebeachsomewhere was 1 and Cam Fella was 2 and finished like it did above you would win the exactor payout. Since you bet a 1 dollar exactor you would get 14.00 or half the

$2 dollar payout.

**Boxed Exactor**

You can play a box Exactor which means your numbers can finish in any order, and you still win. So if you did a 1 dollar box exactor 1-2 in the above scenario you would win ½ the payout since the Exactor payout is based on a 2 dollar wager, or 14 dollars for your 2 dollars investment.

You can play more than 2 horses in a Boxed exactor.

If you boxed 1-2-3 in the above case it would cost you 6 dollars (1 dollar for each combination times 6 different combinations)

If you were to box 4 horses, it would cost 12 dollars. (1 dollar times 12 combinations)

The easiest way to figure out the cost is multiply (the total number of horses) by 1 less.

So 3 horse box costs 3 x 2 or 6 combinations x your bet amount. If you bet a 1 dollar box its $6.00

4 horse box costs 4 x 3 or 12 combinations x your bet amount. If you bet a 1 dollar box its $12.00

This also works with triactors.

3 horse box 3 x 2 x 1 or 6 combinations times the dollar amount wagered

4 horse box 4 x 3 x 2 or 24 combinations times the dollar amount wagered

So a 1 dollar triactor box 1-2-3 would cost 6 dollars, and a 1 dollar triactor box 1-2-3-4 would cost 24 dollars.

**Wheeled Exactor**

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If you want to play the exactor or triactor but don’t want to spend 12 or 24 dollars, you can WHEEL a horse and reduce your expense.

Lets say you really like Somebeachsomewhere, but aren’t sure he will win, you could do a wheel exactor 1 with any number of horses in 2^{nd} place, and if you think he might be 2^{nd}, you could reverse it, with any number of horses with 1. (example. 1 with 2345 and 2345 with 1)

Lets say I like 1-2-3, and I think Somebeachsomewhere number 1 is going to be 1^{st} or 2^{nd}.

I could do a 1 dollar wheel exactor 1 with 2-3, and 2-3 with 1. The total cost is only 4 dollars, and Somebeachsomewhere has to finish 1^{st} or 2^{nd}, with Cam Fella or A Worthy Lad 1^{st} or 2^{nd} in order for me to win. Since it’s a 1 dollar wager, I would get half the payout, which is based on a 2 dollar wager.

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**Triactor Wheel**

You can do the same exact thing with triactors. Again to find out how much it was cost, simply multiply the 1^{st} group of horses, by the 2^{nd} group minus 1 horse…(unless no horses are the same) (ie. 1 with 2 with 3-4-5-6-7 would cost 1 x 1 x 5, multiplied by the dollar amount per wager)

So If I had a 7 horse race and I bet 1 dollar triactor (1 with All with All) it would cost me

One x 6 horses x 5 horses or 30 dollars total. If Somebeachsomewhere won, and I had all for 2^{nd} and 3^{rd}, I would win half the triactor payout. You can wheel as many horses as you want in each position.

For example, 1 dollar triactor wheel 1 with 2-3-4 with 2-3-4-5-6-7.

In this scenario, 1 must win, 2, 3 or 4 must be 2^{nd}, and 2,3,4,5, 6 or 7 must be third.

The cost would be 1 x 3 x 5, (since the 2, 3 and 4 horses are in both places) you can’t have a 1-2-2 triactor, or a 1-4-4 triactor…..

The actual potential winning combinations on your ticket would be

1-2-3, 1-2-4, 1-2-5, 1-2-6, 1-2-7, 1-3-2, 1-3-4, 1-3-5, 1-3-6, 1-3-7, 1-4-2, 1-4-3, 1-4-5, 1-4-6, and 1-4-7. 15 combinations x 1 dollar per combination equals $15 dollars.

If you have any questions, you can go to the information area of the Mutuels, or ask Gord Dougan or Andrew Hughes who will be happy to help.